# Make a list of evenly spaced numbers in a certain range of python

What is a pythonic way of making list of arbitrary length containing evenly spaced numbers (not just whole integers) between given bounds? For instance:

```my_func(0,5,10) # ( lower_bound , upper_bound , length )
# [ 0, 0.5, 1, 1.5, 2, 2.5, 3, 3.5, 4, 4.5 ]```

Note the `Range()`
function only deals with integers. And this:

```def my_func(low,up,leng):
list = []
step = (up - low) / float(leng)
for i in range(leng):
list.append(low)
low = low + step
return list```

seems too complicated. Any ideas?

Given numpy, you could use linspace
:

Including the right endpoint (5):

```In [46]: import numpy as np
In [47]: np.linspace(0,5,10)
Out[47]:
array([ 0.        ,  0.55555556,  1.11111111,  1.66666667,  2.22222222,
2.77777778,  3.33333333,  3.88888889,  4.44444444,  5.        ])```

Excluding the right endpoint:

```In [48]: np.linspace(0,5,10,endpoint=False)
Out[48]: array([ 0. ,  0.5,  1. ,  1.5,  2. ,  2.5,  3. ,  3.5,  4. ,  4.5])```