# 排序列表转化为二分查找树

2017-07-11

```2
1->2->3  =>   /
1   3```
```import java.util.Scanner;
/**
*
* 给出一个所有元素以升序排序的单链表，将它转换成一棵高度平衡的二分查找树

2
1->2->3  =>   /
1   3
* @author Dell
*
*/
public class Test106 {
{
TreeNode result=null;
return result;
{
return result;
}
if(result==null)
{
result=new TreeNode(mid.val);
}
ListNode pre=null;
while(q!=mid)
{
if(q.next==mid)
{
pre=q;
break;
}
q=q.next;
}
if(pre!=null)
pre.next=null;
else
ListNode post=mid.next;
mid.next=null;
result.right=sortedListBST(post);
return result;
}

{
while(fast.next!=null&&fast.next.next!=null)
{
slow=slow.next;
fast=fast.next.next;
}
return slow;
}
public static void preorder(TreeNode t)
{
if(t!=null)
{
System.out.print(t.val+" ");
preorder(t.left);
preorder(t.right);
}

}
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
int n=sc.nextInt();
ListNode list=new ListNode(-1);
ListNode p=list;
for(int i=0;i<n;i++)
{
ListNode temp=new ListNode(sc.nextInt());
p.next=temp;
p=p.next;
}
TreeNode result=sortedListBST(list.next);
preorder(result);
}

}```

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